Classify CPU usage as OK, warning or critical
easyIf and else Must-do
Problem statement
Monitoring tools map a number to a severity. Given cpu as a percentage, print:
OKif it is below 70WARNINGif it is 70 or more but below 90CRITICALif it is 90 or more
Examples
Example 1
Input: cpu = 87
Output: WARNING
Explanation: 87 is at least 70 but below 90.
Hints
Approach
Optimal
When there are more than two outcomes, add elif ("else if") branches between if and else. Python tests each condition in order and runs only the first block whose condition is true, then skips the rest. That is why the second check can be just cpu < 90: to reach it, cpu < 70 must already have been false. The comparison operators are <, <=, >, >=, == and !=.
Python
cpu = 87 if cpu < 70: print("OK")elif cpu < 90: print("WARNING")else: print("CRITICAL")Follow-up questions
- Put the thresholds 70 and 90 in variables named
WARNandCRIT. - Print the value too, for example
cpu=87% WARNING.
Frequently asked questions
Yes. If you check cpu < 90 first, a value of 50 would print WARNING, because that condition is also true for it. Order checks from the most specific or lowest range upward.